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Configuration = 47
cycles = (10 5 3 9 4)(8 6 1 7 2)

a = 1, b = 3, c = 9
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cycles = (10 3 1 5 8 6 4 7 2)(9)

a = 1, b = 5, c = 8
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cycles = (10 6 4 2 7 3 5)(9)(8)(1)

a = 3, b = 5, c = 10
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cycles = (10)(9 2 5 8 4)(7)(6)(3)(1)

a = 2, b = 5, c = 9
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cycles = (10)(9 5 8)(7)(6)(4)(3)(2)(1)